EXCEL下使用MATCH函数碰到的问题
发表于:2007-06-30来源:作者:点击数:
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Sub USEMATCH() Dim s_p As String, e_p As String Dim num As Integer num = 0 For Each M In Range("a:a") If M.Value "" Then num = num + 1 Else Exit For End If Next M erange = "b" num erange = "b2:" erange N = 1 a = 2 currange = "b" a Cells.Se
Sub USEMATCH()
Dim s_p As String, e_p As String
Dim num As Integer
num = 0
For Each M In Range("a:a")
If M.Value <> "" Then
num = num + 1
Else
Exit For
End If
Next M
erange = "b" & num
erange = "b2:" & erange
N = 1
a = 2
currange = "b" & a
Cells.Select
Selection.Sort Key1:=Range("A2"), Order1:=xlAscending, Key2:=Range("B2") _
, Order2:=xlAscending, Header:=xlGuess, OrderCustom:=1, MatchCase:= _
False, Orientation:=xlTopToBottom, SortMethod:=xlPinYin, DataOption1:= _
xlSortNormal, DataOption2:=xlSortNormal
Columns("A:A").Select
Selection.Insert Shift:=xlToRight @#最左插入一列
Set curCell = Worksheets(Sheets(1).Name).Range(currange)
For Each M In Range(erange)
On Error GoTo ErrorHandler
If M.Offset(0, -1).Value <> "" Then GoTo mynext
If M.Offset(0, 1).Value = "" Then GoTo mynext @#当前单元格左不为空/右单元格内容为空则转
s_p = M.Value: e_p = M.Offset(0, 1).Value
pos = Application.WorksheetFunction.Match(e_p, Worksheets(1).Range(erange), 0) @#查找终点在起点列出现的行数
If pos = "" Then
curCell.Offset(0, -1).Value = "NO"
GoTo mynext @#若没有找到则设为"no"
End If
thenext:
Position = "B" & Trim(Str(pos)) @#定位到所在单元格
If Range(Position).Offset(0, 1).Value = s_p Then
If Range(Position).Offset(0, -1) = "" Then @#若符合条件则在对应记录前标记
curCell.Offset(0, -1).Value = N & ".A"
Range(Position).Offset(0, -1).Value = N & ".B"
N = N + 1
Else
curCell.Offset(0, -1).Value = "NO"
End If
Else
If Range(Position).Offset(1, 0).Value = e_p Then
pos = pos + 1
GoTo thenext
Else
curCell.Offset(0, -1).Value = "NO"
End If
End If
myVar = 0
mynext:
a = a + 1
currange = "b" & a
Set curCell = Worksheets(Sheets(1).Name).Range(currange)
Next
ErrorHandler:
curCell.Offset(0, -1).Value = "NO"
Resume Next
End Sub
表格形式为:A列 和B列. 匹配条件是:按行查询,若第一行的A列单元格内容等于另一行B列单元格内容,就检查第一行B列单元格内容是否等于另一行A列单元格内容,若相等就在这两行前做标记.否则标记为NO
原文转自:http://www.ltesting.net