我的BSOOC里需要一个查询表主键外键信息的SQL，昨晚研究到凌晨1点，终于能实现这个目标：
Oracle:
select o.obj# as objectId, o.name AS tableName, oc.name AS constraintName,
decode(c.type#, 1, @#C@#, 2, @#P@#, 3, @#U@#,
4, @#R@#, 5, @#V@#, 6, @#O@#, 7,@#C@#, @#?@#) as constraintType,
col.name AS columnName
from sys.con$ oc, sys.con$ rc,
sys.obj$ ro,sys.obj$ o, sys.obj$ oi,
sys.cdef$ c,
sys.col$ col, sys.ccol$ cc, sys.attrcol$ ac
where oc.con# = c.con#
and c.obj# = o.obj#
and c.rcon# = rc.con#(+)
and c.enabled = oi.obj#(+)
and c.robj# = ro.obj#(+)
and c.type# != 8
and c.type# != 12 /* don@#t include log groups */
and c.con# = cc.con#
and cc.obj# = col.obj#
and cc.intcol# = col.intcol#
and cc.obj# = o.obj#
and col.obj# = ac.obj#(+)
and col.intcol# = ac.intcol#(+)
and o.name = @#your table@#
SQL Server:
SELECT sysobjects.id objectId,
OBJECT_NAME(sysobjects.parent_obj) tableName,
sysobjects.name constraintName,
sysobjects.xtype AS constraintType,
syscolumns.name AS columnName
FROM sysobjects INNER JOIN sysconstraints
ON sysobjects.xtype in(@#C@#, @#F@#, @#PK@#, @#UQ@#, @#D@#)
AND sysobjects.id = sysconstraints.constid
LEFT OUTER JOIN syscolumns ON sysconstraints.id = syscolumns.id
WHERE OBJECT_NAME(sysobjects.parent_obj)=@#your table@#
其它数据库还没时间去实现.
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